Given a singly linked list, return a random node’s value from the linked list. Each node must have the same probability of being chosen.
Follow up:
What if the linked list is extremely large and its length is unknown to you? Could you solve this efficiently without using extra space?
Example:
// Init a singly linked list [1,2,3].
ListNode head = new ListNode(1);
head.next = new ListNode(2);
head.next.next = new ListNode(3);
Solution solution = new Solution(head);
// getRandom() should return either 1, 2, or 3 randomly. Each element should have equal probability of returning.
solution.getRandom();
/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param head The linked list's head.
Note that the head is guaranteed to be not null, so it contains at least one node.
* @param {ListNode} head
*/
var Solution = function(head) {
this.head = head;
};
/**
* Returns a random node's value.
* @return {number}
*/
Solution.prototype.getRandom = function() {
var total = 1;
var p = this.head;
while(p.next !== null){
p = p.next;
total++;
}
var index = Math.floor(Math.random() * Math.floor(total))
var p = this.head;
for(var i=0;i<index;i++){
p = p.next;
}
return p.val;
};
/**
* Your Solution object will be instantiated and called as such:
* var obj = new Solution(head)
* var param_1 = obj.getRandom()
*/
Random Set- Phone Interview
CompletedJune 1, 2019 7:41 AM
Time Spent: 38 minutes 29 seconds
Time Allotted: 1 hour 30 minutes
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Find Pivot Index
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Linked List Random Node
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